Most thanked 2025 - Quarry

This query is marked as a draft This query has been published by Hey man im josh.

SQL

SELECT RANK() OVER (ORDER BY `Times thanked` DESC) AS 'Rank', log_title AS 'User', COUNT(log_id) AS 'Times thanked'
FROM logging_logindex
WHERE 
	log_type = "thanks" AND
    log_timestamp >= "20250000000000"
GROUP BY log_title
ORDER BY 'Times thanked' DESC

AخA
 
SELECT RANK() OVER (ORDER BY `Times thanked` DESC) AS 'Rank', log_title AS 'User', COUNT(log_id) AS 'Times thanked'FROM logging_logindexWHERE     log_type = "thanks" AND    log_timestamp >= "20250000000000"GROUP BY log_titleORDER BY 'Times thanked' DESC

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