avg time in weekday

This query is marked as a draft This query has been published by Jula23.

SQL

select count(*), year(rev_timestamp) AS "year", month(rev_timestamp) AS "month",DATENAME(WEEKDAY, left(rev_timestamp, 8)) as "day",
avg(hour(rev_timestamp))
from revision
where left(rev_timestamp, 4) in (2019, 2020, 2021, 2022, 2023)
group by 2,3,4;

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