Untitled query #61375

This query is marked as a draft This query has been published by TheDJ.

SQL

SELECT  page_namespace AS `namespace`,
	page_title AS `title`,
    0 AS `value`  FROM `page`
 LEFT OUTER JOIN `image` ON ((substr( page_title, 1, length( page_title ) - length( substring_index( page_title, '.' ,-2 ) ) - 1 ) = img_name))
 WHERE img_name IS NULL AND page_namespace = 0
 ORDER BY namespace,title LIMIT 51

By running queries you agree to the Cloud Services Terms of Use and you irrevocably agree to release your SQL under CC0 License.

Submit Query Stop Query

All SQL code is licensed under CC0 License.

SQL

Checking query status...