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أكثر المستخدمين امتلاكًا للصلاحيات في ويكيبيديا العربية
by
ASammour
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by
Nehaoua
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use arwiki_p; select user_name, count(ug_group), group_concat(ug_group) from user inner join user_groups on ug_user = user_id group by user_id order by count(ug_group) desc limit 100;
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