Untitled query #24944

This query is marked as a draft This query has been published by SQL.

select * from user where (user_name like "%/%" OR user_name like "%?%" OR user_name like "%&%") AND user_name like "%=%";

AخA
 
select * from user where (user_name like "%/%" OR user_name like "%?%" OR user_name like "%&%") AND user_name like "%=%";

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