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SELECT CONCAT('Catégorie:', subcat_page.page_title) AS subcategory_name, COUNT(cl2.cl_from) AS member_count FROM categorylinks AS cl1 JOIN page AS subcat_page ON cl1.cl_from = subcat_page.page_id JOIN categorylinks AS cl2 ON cl2.cl_to = subcat_page.page_title WHERE subcat_page.page_namespace = 14 AND cl1.cl_to = 'Article de qualité dans une autre langue' GROUP BY subcat_page.page_title HAVING member_count < 10 ORDER BY member_count ASC;
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