Toggle navigation
Home
New Query
Recent Queries
Discuss
Database tables
Database names
MediaWiki
Wikibase
Replicas browser and optimizer
Login
History
Fork
This query is marked as a draft
This query has been published
by
Abhishek02bhardwaj
.
Toggle Highlighting
SQL
SELECT COUNT(DISTINCT r.rev_actor) AS distinct_user_count, COUNT(DISTINCT b.babel_user) AS has_babel_count FROM actor LEFT JOIN babel b ON a.actor_user = b.babel_user;
By running queries you agree to the
Cloud Services Terms of Use
and you irrevocably agree to release your SQL under
CC0 License
.
Submit Query
Stop Query
All SQL code is licensed under
CC0 License
.
Checking query status...