| SELECT COUNT(*) AS "# Articles", SUM(page_len) / COUNT(*) AS "Average Size",... |
1 year ago |
| SELECT COUNT(*), SUM(page_len) / COUNT(*) AS "Average Size", actor_name
FROM... |
1 year ago |
| SELECT COUNT(*), SUM(page_len) / COUNT(*) AS "Average Size", actor_name
FROM... |
1 year ago |
