Untitled query #61375

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SQL

SELECT  page_namespace AS `namespace`,page_title AS `title`,0 AS `value`  FROM `page` LEFT OUTER JOIN `image` ON ((substr( page_title, 1, length( page_title ) - length( substring_index( page_title, '.' ,-2 ) ) - 1 ) = img_name))   WHERE img_name IS NULL AND page_namespace = 0  ORDER BY namespace,title LIMIT 51

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