New test - Quarry

This query is marked as a draft This query has been published by Alexander Misel.

SQL

SELECT RANK() OVER (ORDER BY sl DESC) rank, actor_name, sl FROM
(SELECT actor_name, user_id, COUNT(*) sl FROM revision
JOIN page ON rev_page = page_id
JOIN actor ON rev_actor = actor_id
JOIN `user` ON actor_user = user_id
WHERE page_namespace = 0 AND rev_timestamp > DATE_FORMAT(NOW() - INTERVAL 7 DAY, '%Y%m%d%H%i%s')
GROUP BY actor_name
) aaa
WHERE NOT EXISTS (SELECT * FROM user_groups WHERE ug_user = user_id AND ug_group = 'bot')
ORDER BY sl DESC

By running queries you agree to the Cloud Services Terms of Use and you irrevocably agree to release your SQL under CC0 License.

Submit Query Stop Query

All SQL code is licensed under CC0 License.

SQL

Checking query status...