select
user_name,
count(*) as subpage_count
from (select
page_id... |
3 years ago |
select
user_name
count(*) as subpage_count
from (select
page_id as... |
3 years ago |
use enwiktionary_p;
select
count(*) as count,
user_name
from (select
... |
4 years ago |
use enwiktionary_p;
select
count(*) as count,
user_name
from (select
... |
4 years ago |
use enwiktionary_p;
select
count(*) as count,
ns, user_name,... |
4 years ago |