Untitled query #47938

This query is marked as a draft This query has been published by AlanM1.

SQL

-- select user_name from user where UPPER(user_name) like '%chandandolui%';
/*
SELECT
  'abcde' LIKE '%bcd%' AS a
, 'abcde' LIKE '%bcd%' AS b
, 'ABCDE' LIKE '%BCD%' AS c
, 'ABCDE' LIKE '%BCD%' AS d
, 'Abcde' LIKE '%bcd%' AS e
, 'AbCdE' LIKE '%bcd%' AS f
, 'Abcde' LIKE '%bCd%' AS g
, 'AbCdE' LIKE '%bCd%' AS h
;
*/
select 'abcde' LIKE '%bcd';

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