Test 3 - Quarry

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SQL

SELECT DISTINCT en_cats.page_title
FROM categorylinks en_cats
LEFT JOIN (
  SELECT DISTINCT ll_from
  FROM langlinks
  WHERE ll_lang = 'ckb'
) AS ckb_categories ON en_cats.cl_from = ckb_categories.ll_from
WHERE
  en_cats.cl_to NOT LIKE 'Hidden%'
  AND ckb_categories.ll_from IS NULL
LIMIT 100;

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