Test 3 - Quarry

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SQL

SELECT DISTINCT
  cl_to AS category_title,
  COUNT(ll_lang) AS language_count
FROM categorylinks
LEFT JOIN page ON cl_from = page_id
LEFT JOIN langlinks ON page_id = ll_from
WHERE
  cl_to NOT LIKE 'Hidden_categories'
  AND ll_from IS NOT NULL
  AND ll_lang != 'ckb'
GROUP BY category_title
ORDER BY language_count DESC
LIMIT 100;

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