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English Wiktionary edits-per-day leaderboard for 2020
by
Erutuon
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SQL
use enwiktionary_p; select date_format(rev_timestamp, '%Y-%m-%d') as day, actor_name, count(*) as count from revision join actor on actor_id = rev_actor where rev_timestamp like '2020%' or rev_timestamp like '20191%' group by substring(rev_timestamp, 1, 8), actor_name order by count(*) desc limit 1000;
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