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This query is marked as a draft
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by
Erutuon
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Times one person has thanked another on English Wiktionary.
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SQL
select actor_name as thanker, log_title as thanked, count(*) as times from logging_userindex join actor on actor_id = log_actor where log_type = 'thanks' group by log_actor, log_title having times >= 15 order by times desc;
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