Top missing - Quarry

This query is marked as a draft This query has been published by MirrorWuu.

Thanks for the coding.

SQL

SELECT page_title AS `title`, COUNT(*) AS `languages`
	FROM `langlinks` LEFT JOIN `page` ON (page_id = ll_from)
	WHERE page_namespace = '0' AND page_id NOT IN (SELECT ll_from FROM `langlinks` WHERE ll_lang='wuu')
	GROUP BY page_namespace, page_title
	HAVING languages > 40
	ORDER BY languages DESC

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