uit n/a = - Quarry

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SQL

use wikidatawiki_p; 
SELECT 
	CONCAT('Q', term_entity_id) As item, 
    #	term_language As lang,
	CONCAT('"', term_text, '"') As descr,
	CURRENT_DATE
from wb_terms 
WHERE term_entity_type = 'item' 
		AND term_language = 'nl' 
		AND term_type = 'description'    # 'label', 'alias'
		AND term_text LIKE '%uit n/a = (%)'
GROUP BY term_text, term_entity_id

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